Two parallel large thin metal sheets have equal surface charge densities `(sigma = 26.4 xx 10^(-12) C//m^(2))` of opposite signs. The electric field between these sheets is

Options

A. `1.5 N//C`
B. `1.5 xx 10^(-10)N//C`
C. `3N//C`
D. `3xx10^(-10)N//C`

Answer

C

Explanation

The situation is shown in the figure. Plate 1 has surface charge density `sigma` and plate 2 has surface charge density `-sigma` . The electric fields at point P due to two charged plates add up, giving

`E=(sigma)/(2epsilon_(0))+(sigma)/(2epsilon_(0))=(sigma)/(epsilon_(0))`
Given, `sigma =26.4xx10^(-12)C/m^(2)`
`sigma_(0)=8.85xx10^(-12)C^(2)//Nm^(2)`
Hence, `E=(26.4xx10^(-12))/(8.85xx10^(-12))=3N//C`