The Young's double slit experiment is carried out with light of wavelength `5000Å`. The distance between the slits is `0.2 mm` and the screen is at `200 cm` from the slits. The central maximum is at `y=0`. The third maximum will be at `y` equal to

Options

A. 5 cm
B. 0.5 m
C. 1.67 cm
D. 1.5 cm

Answer

D

Explanation

Here, `y_(n)(6)=n lambda (D)/(d)`
Given that `n=3, lambda = 5000` Å
`5000 xx 10^(-10)m`
`D=2m`
and `d=0.2 mm=0.2 xx 10^(-3)m`
Hence, `y_(n)(6)=(3xx5000xx10^(-10) xx 2)/(0.2xx10^(-3))`
`=15xx10^(-3)`
`=1.5 cm`