A galvanometer has a current sensitivity...

A galvanometer has a current sensitivity of 4 div/microampere. If the resistance of the galvanometer is `100 Omega`, its voltage sensitivitiy will be

`2xx10^(3)`div/volt

200 div/volt

`2xx10^(4)` div/volt

`2xx10^(5)` div/volt

Text Solution

Verified by Experts

The correct Answer is:

`V.S=(C.S)/(R )=(4"div"//muA)/(200 Omega)`
`=(4xx10^(6)"div"//A)/(200Omega)`
`=2xx10^(4)"div"//V`

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