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What is the equivalent weight of "SnCl"(...

What is the equivalent weight of `"SnCl"_(2)` in the following reaction ?
`"SnCl"_(2)+"Cl" to "SnCl"_(4)("Mol. Wt. of SnCl"_(2)=190)`

A

95

B

45

C

60

D

30

Text Solution

Verified by Experts

The correct Answer is:
A

`underset(190)("SnCl"_(2))+underset(71)("Cl"_(2))to"SnCl"_(4)`
Eq. wt. of `"SnCl"_(2)="Eq. wt. of"Cl_(2)`
`:." "(190)/(E_(1))=(71)/(35.5)" or "E_(1)=95`
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