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Dual of (x vv y) ^^ (x vv 1) = x vv x ^^...

Dual of `(x vv y) ^^ (x vv 1) = x vv x ^^ y vv y` is

A

`(x*y)+(x*0)=x)(x+y)*y`

B

`(x+y)+(x*1)=x*(x+y)*y`

C

`(c*y)*(x*0)=x*(x+y)*y`

D

None of these above

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The correct Answer is:
A
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-PRACTICE SET 21-PAPER 2 (MATHEMATICS)
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