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If A+B+C=piandsinC+sinAcosB=0, then tanA...

If `A+B+C=piandsinC+sinAcosB=0`, then tanA.cotB is equal to

A

0

B

`-(1)/(2)`

C

1

D

-1

Text Solution

Verified by Experts

The correct Answer is:
B

`A+B+C=pi`
`impliessinC+sinAcosB=0`
`sin[pi-(A+B)]+sinAcosB=0`
`sin(A+B)+sinAcosB=0`
`sinAcosB+cosAsinB+sinAcosB=0`
`2sinAcosB+cosAsinB=0`
`2sinAcosB=-cosAsinB`
`impliestanAcotB=(-1)/(2)`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-FACTORIZATION FORMULAE -EXERCISE 2
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  16. tan2 0^0tan4 0^0tan6 0^0tan8 0^0

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  18. If A, B, C, D be the angles of acyclic quadrilateral, show that : cosA...

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  19. If A+B+C=pi, prove that : (cosA)/(sinb sinC) + (cosB)/(sinC sin) + (co...

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