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If A+B+C=270^@ , then cos2A+cos2B+cos2C...

If `A+B+C=270^@` , then `cos2A+cos2B+cos2C+4sinAsin B sinC=`

A

0

B

1

C

2

D

3

Text Solution

Verified by Experts

The correct Answer is:
B
`A+B+C=270^(@)`
`implies A=B=C=90^(@)`, then
`cos2A+cos2B+cos2C+4sinAsinBsinC`
`=cos180^(@)+cos180^(@)+cos180^(@)+4sin90^(@)sin90^(@)sin90^(@)`
`=-1-1+4.1.1.1`
`=-3+4=1`
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