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The ratio by which the line 2x + 5y -7=0...

The ratio by which the line 2x + 5y -7=0 divides the straight line joining the points (-4,7) and (6,-5) is

A

`1:4`

B

`1:2`

C

`1:1`

D

`2:3`

Text Solution

Verified by Experts

The correct Answer is:
C

Let the given line divides the line joining two points in the ratio ` m_(1):m_(2)`

Coordinates of P ` = ((6m_(1) -4m_(2))/(m_(1)+m_(2)) , (-5m_(1) +7m_(1))/(m_(1)+m_(2)))`
Since the point P lies on the line
2x + 5y -7=0
` 2((6m_(1)-4m_(2))/(m_(1)+m_(2))) + 5((-5m_(1) +7m_(2))/(m_(1) + m_(2))) -7=0`
`Rightarrow 12m_(1) -8m_(2) -25m_(1) +35m_(2)-7m_(1) -7m_(2)=0`
` Rightarrow -20m_(1)+20m_(2)=0`
`Rightarrow m_(1) =m_(2)`
`Rightarrow m_(1)/m_(2) =1/1`
` therefore m_(1):m_(2)=1:1`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-STRAIGHT LINE -EXERCISE 2(MISCELLANEOUS PROBLEMS)
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  16. The st. lines 3x + 4y =5 and 4x-3y = 15 interrect at a point A(3,-1)....

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