Home
Class 12
MATHS
The position of reflection of the point ...

The position of reflection of the point (4,1) about the line y=x -1 is

A

1,2

B

3,4

C

`-1,0`

D

2,3

Text Solution

AI Generated Solution

The correct Answer is:
To find the position of the reflection of the point \( P(4, 1) \) about the line \( y = x - 1 \), we can follow these steps: ### Step 1: Identify the line and the point The line of reflection is given by the equation \( y = x - 1 \). The point to be reflected is \( P(4, 1) \). ### Step 2: Find the coordinates of point R on the line Let the coordinates of point \( R \) (the foot of the perpendicular from \( P \) to the line) be \( (h, k) \). Since \( R \) lies on the line \( y = x - 1 \), we can express \( k \) in terms of \( h \): \[ k = h - 1 \] ### Step 3: Calculate the slope of line PR The slope of line \( PR \) can be calculated using the formula for the slope between two points: \[ \text{slope of } PR = \frac{k - 1}{h - 4} \] Substituting \( k = h - 1 \): \[ \text{slope of } PR = \frac{(h - 1) - 1}{h - 4} = \frac{h - 2}{h - 4} \] ### Step 4: Determine the slope of the line of reflection The slope of the line \( y = x - 1 \) is \( 1 \). ### Step 5: Use the property of perpendicular lines Since \( PR \) is perpendicular to the line of reflection, the product of their slopes must equal \(-1\): \[ \frac{h - 2}{h - 4} \cdot 1 = -1 \] This simplifies to: \[ h - 2 = - (h - 4) \] \[ h - 2 = -h + 4 \] Adding \( h \) to both sides: \[ 2h - 2 = 4 \] Adding \( 2 \) to both sides: \[ 2h = 6 \] Dividing by \( 2 \): \[ h = 3 \] ### Step 6: Find the value of k Substituting \( h = 3 \) back into the equation for \( k \): \[ k = h - 1 = 3 - 1 = 2 \] Thus, the coordinates of point \( R \) are \( (3, 2) \). ### Step 7: Use the midpoint formula to find Q Since \( R \) is the midpoint of \( P \) and \( Q \), we can use the midpoint formula: \[ R = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \] Let \( Q = (a, b) \). Then: \[ 3 = \frac{4 + a}{2} \quad \text{and} \quad 2 = \frac{1 + b}{2} \] ### Step 8: Solve for a and b From the first equation: \[ 3 \cdot 2 = 4 + a \implies 6 = 4 + a \implies a = 2 \] From the second equation: \[ 2 \cdot 2 = 1 + b \implies 4 = 1 + b \implies b = 3 \] ### Conclusion The coordinates of the reflection point \( Q \) are \( (2, 3) \). Thus, the position of the reflection of the point \( (4, 1) \) about the line \( y = x - 1 \) is \( \boxed{(2, 3)} \).

To find the position of the reflection of the point \( P(4, 1) \) about the line \( y = x - 1 \), we can follow these steps: ### Step 1: Identify the line and the point The line of reflection is given by the equation \( y = x - 1 \). The point to be reflected is \( P(4, 1) \). ### Step 2: Find the coordinates of point R on the line Let the coordinates of point \( R \) (the foot of the perpendicular from \( P \) to the line) be \( (h, k) \). Since \( R \) lies on the line \( y = x - 1 \), we can express \( k \) in terms of \( h \): \[ ...
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINE

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise EXERCISE 2(MISCELLANEOUS PROBLEMS)|30 Videos
  • SOLVED PAPER 2019

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MCQS|150 Videos
  • THREE DIMENSIONAL GEOMETRY

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|3 Videos

Similar Questions

Explore conceptually related problems

The reflection of the point (6,8) in the line x=y is

Find the reflection of a point (2,3) along the line y=-x

What is the reflection of the point (-3,1) in the line x=-2

The reflection of the point (-3,-2) about Y - axis is

The co-ordinates of the point of reflection of the origin (0,0) in the line 4x-2y-5=0 is

The point Q is the image of the point P(1,5) about the line y=x and R is the image of the point Q about the line y= -x . The circumcentre of the DeltaPQR is

MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-STRAIGHT LINE -EXERCISE 2(MISCELLANEOUS PROBLEMS)
  1. The position of reflection of the point (4,1) about the line y=x -1 is

    Text Solution

    |

  2. A straight line L through the point (3,-2) is inclined at an angle 60^...

    Text Solution

    |

  3. If a striaght line passes through the points (-1/2,1) and (1,2) then ...

    Text Solution

    |

  4. The equation of the line passing through (0,0) and intersection point ...

    Text Solution

    |

  5. Determine the ratio in which the line 3x+y-9=0 divides the segment ...

    Text Solution

    |

  6. The equations y= +-sqrt3 x,y =1 are the sides of

    Text Solution

    |

  7. The slopes of the lines, which make an angle 45^(@) with the line 3x -...

    Text Solution

    |

  8. The image of the origin with reference to the line 4x+3y -25=0 is

    Text Solution

    |

  9. The length of perpendicular from the point ( a cos prop, a sin prop) ...

    Text Solution

    |

  10. L is a variable line such that the algebraic sum of the distances of ...

    Text Solution

    |

  11. The perpendicular bisector of the line segment joining P (1, 4) and ...

    Text Solution

    |

  12. A line passes through the point of intersection of the line 3x+y+1=0 a...

    Text Solution

    |

  13. The point P(a,b) lies on the straight line 3x+2y=13 and the point Q(b,...

    Text Solution

    |

  14. The equations of the perpendicular bisectors of the sides A Ba n dA C ...

    Text Solution

    |

  15. If the lines kx-2y-1=0 and 6x-4y-m=0 are identical (coindent) lines, t...

    Text Solution

    |

  16. The st. lines 3x + 4y =5 and 4x-3y = 15 interrect at a point A(3,-1)....

    Text Solution

    |

  17. The line passing through the point of intersection of x + y = 2,x-y = ...

    Text Solution

    |

  18. The equation of the line passing through the point of intersection of ...

    Text Solution

    |

  19. A ray of light along x+sqrt(3)y=sqrt(3) gets reflected upon reaching ...

    Text Solution

    |

  20. If (sin theta, cos theta) and (3,2) lie on the same side of the line x...

    Text Solution

    |

  21. The equation to the line bisecting the join of (3,-4) and (5,2) and ha...

    Text Solution

    |