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The image of the origin with reference t...

The image of the origin with reference to the line 4x+3y -25=0 is

A

`(-8,6)`

B

8,6

C

`-3,4`

D

`8,-6`

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To find the image of the origin (0, 0) with respect to the line given by the equation \(4x + 3y - 25 = 0\), we can follow these steps: ### Step 1: Identify the equation of the line The equation of the line is given as: \[ 4x + 3y - 25 = 0 \] ### Step 2: Set the coordinates of the image Let the coordinates of the image of the origin be \((h, k)\). ### Step 3: Find the midpoint of the origin and its image The midpoint \(M\) of the segment joining the origin \((0, 0)\) and the image \((h, k)\) is given by: \[ M = \left(\frac{h + 0}{2}, \frac{k + 0}{2}\right) = \left(\frac{h}{2}, \frac{k}{2}\right) \] ### Step 4: Substitute the midpoint into the line equation Since the midpoint lies on the line, we substitute \(\left(\frac{h}{2}, \frac{k}{2}\right)\) into the line equation: \[ 4\left(\frac{h}{2}\right) + 3\left(\frac{k}{2}\right) - 25 = 0 \] This simplifies to: \[ 2h + \frac{3k}{2} - 25 = 0 \] Multiplying through by 2 to eliminate the fraction gives: \[ 4h + 3k - 50 = 0 \quad \text{(Equation 1)} \] ### Step 5: Find the slope of the line The slope of the line \(4x + 3y - 25 = 0\) can be calculated from the coefficients: \[ \text{slope} = -\frac{\text{coefficient of } x}{\text{coefficient of } y} = -\frac{4}{3} \] ### Step 6: Find the slope of the line joining the origin and the image The slope of the line joining the origin \((0, 0)\) and the image \((h, k)\) is: \[ \text{slope} = \frac{k - 0}{h - 0} = \frac{k}{h} \] ### Step 7: Set up the perpendicularity condition Since the two lines are perpendicular, the product of their slopes must equal \(-1\): \[ \frac{k}{h} \cdot \left(-\frac{4}{3}\right) = -1 \] This simplifies to: \[ \frac{4k}{3h} = 1 \implies 4k = 3h \quad \text{(Equation 2)} \] ### Step 8: Solve the equations From Equation 2, we can express \(k\) in terms of \(h\): \[ k = \frac{3h}{4} \] Substituting this into Equation 1: \[ 4h + 3\left(\frac{3h}{4}\right) - 50 = 0 \] This simplifies to: \[ 4h + \frac{9h}{4} - 50 = 0 \] Multiplying through by 4 to eliminate the fraction: \[ 16h + 9h - 200 = 0 \implies 25h = 200 \implies h = 8 \] ### Step 9: Find \(k\) Now substituting \(h = 8\) back into the equation for \(k\): \[ k = \frac{3 \cdot 8}{4} = 6 \] ### Step 10: Conclusion The coordinates of the image of the origin with respect to the line \(4x + 3y - 25 = 0\) are: \[ (h, k) = (8, 6) \]

To find the image of the origin (0, 0) with respect to the line given by the equation \(4x + 3y - 25 = 0\), we can follow these steps: ### Step 1: Identify the equation of the line The equation of the line is given as: \[ 4x + 3y - 25 = 0 \] ...
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-STRAIGHT LINE -EXERCISE 2(MISCELLANEOUS PROBLEMS)
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