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A line passes through the point of intersection of the line `3x+y+1=0` and `2x-y+3=0` and makes equal intercepts with axes. Then, equation of the line is

A

5x+5y-3=0

B

x+5y-3=0

C

5x-y-3=0

D

5x+5y+3=0

Text Solution

Verified by Experts

The correct Answer is:
A

The point of intersection of the lines 3x+y+1=0 and 2x -y+3=0 ` is (-4/5, 7/5)` . The equation of line , which makes equal intercepts with axes, is x+y =a
`-4/5 + 7/5 = a Rightarrow a= 3/5 `
Now required equation of line is x+y `-3/5=0`
5 x+5y -3=0
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-STRAIGHT LINE -EXERCISE 2(MISCELLANEOUS PROBLEMS)
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  13. A straight line through the point (1,1) meets the X-axis at A and Y-ax...

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  14. The equation of the line passing through the point of intersection of ...

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  15. The three straight lines ax+by=c, bx+cy=a and cx +ay =b are collinear,...

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  16. The coordinates of the foot of the perpendicular drawn from the point ...

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  17. If the foot of the perpendicular from the origin to a straight line is...

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  18. The equation of the perpendicular bisector of the line segment joining...

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