The equation of the line passing through the point of intersection of the line `x-3y+2=0` and `2x+5y-7=0` and perpendicular to the line `3x+2y+5=0` is

Options

A. 2x-3y+1=0
B. 6x-9y+11=0
C. 2x-3y+5=0
D. 3x-2y+1=0

Answer

A

Explanation

The coor dinates of apoint of intersection of given lines are (1,1)
The equation of line perpendicular to the line
3x+2y+5=0 is 2x-3y + `lamda` =0 . Since , it is passing through (1,1)
`2-3 + lamda = 0 Rightarrow =0 lamda =1 `
Hence the required equation of line is ` 2x -3y +1 =0`