A ray of light along x+sqrt(3)y=sqrt(3) ...

A ray of light along `x+sqrt(3)y=sqrt(3)` gets reflected upon reaching x-axis, the equation of the reflected ray is

`y=x+sqrt3`

`sqrt3y=x-sqrt3`

`y=sqrt3x -sqrt3`

`sqrt3y=x-1`

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The correct Answer is:

Take any point B(0,1) on given line.

Equation of AB, ` y-0 = (-1-0)/(0-sqrt3)(x -sqrt3)`
` Rightarrow sqrt3 y = -x + sqrt3`
` Rightarrow sqrt3 y = x - sqrt3`

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