Home
Class 12
MATHS
(1+1/(2!)+2/(3!)+(2^(2))/(4!)+(2^(2))/(5...

` (1+1/(2!)+2/(3!)+(2^(2))/(4!)+(2^(2))/(5!)+...)/(1 + 1/(2!)+1/(4!)+1/(6!)+...)` is equal to

A

e/4

B

`betae`

C

e/2

D

` (e(e^(2)-1))/(2(e^(2)+1))`

Text Solution

Verified by Experts

The correct Answer is:
c
` (1/(2^(2))[2^(2)/(2!)+(2^(3))/(3!)+(2^(4))/(3!)+(2^(4))/(4!)+2^(5)/(5!)+...])/(1+1/(2!)+1/(4!)+1/(6!)+...)`
` = (1/(2^(2))[2^(2)+e^(2)-3])/(((e+e^(-1))/2))=e/2`
Promotional Banner

Topper's Solved these Questions

  • SEQUENCES AND SERIES

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise EXERCISE 2|1 Videos

  • SEQUENCES AND SERIES

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise EXERCISE 3|1 Videos

  • PROBABILITY

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|4 Videos

  • SETS, RELATIONS AND FUNCTIONS

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Exercise 2 (MISCELLANEOUS PROBLEMS)|30 Videos

Similar Questions

Explore conceptually related problems

(1+(2^(2))/(2!)+(2^(4))/(3!)+(2^(6))/(4!)+...)/(1+(1)/(2!)+(2)/(3!)+(2^(2))/(4!)+...)=

The sum of the infinite series (1)/(2) ((1)/(3) + (1)/(4)) - (1)/(4)((1)/(3^(2)) + (1)/(4^(2))) + (1)/(6) ((1)/(3^(3)) + (1)/(4^(3))) - ...is equal to