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If one of the lines given by 6x^2- xy +4...

If one of the lines given by `6x^2- xy +4cy^2=0` is `3x +4y=0`, then `c=`

A

1

B

-1

C

3

D

-3

Text Solution

Verified by Experts

The correct Answer is:
D
Here , `a=6,2h=-1,b=4c`
Now , `m_1+m_2=-(2h)/(b)=(1)/(4c),m_1m_2=(a)/(b)=(6)/(4c)`
One line of given pair of lines is `3x+4y=0`.
Slope of line `=-(3)/(4)=m_1`
`therefore -(3)/(4)+m_2=(1)/(4c)`
`rArr m_2=(1)/(4c_+(3)/(4)`
and `(-(3)/(4))((1)/(4c)+(3)/(4))=(6)/(4c)`
`rArr 1+3c=(-6xx4)/(4c)`
`rArr 3c=-9rArr c=-3` .
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