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If the pair of straight lines x^2 - 2pxy...

If the pair of straight lines `x^2 - 2pxy - y^2 = 0` and `x^2 - 2qxy -y^2 = 0` be such that each pair bisects the angle between the other pair, then

A

`pq=-1`

B

`pq=1`

C

`(1)/(p)+(1)/(q)=0`

D

`(1)/(p)-(1)/(q)=0`

Text Solution

Verified by Experts

The correct Answer is:
A
Since , `x^2+(2xy)/(p)-y^2=0`, is the angle bisectors of `x^2-2pxy-y^2=0`
But given that angle bisectors are `x^2-2qxy-y^2=0`
`rArr --2q=2//p`
`therefore pq=1` .
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