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The angle between the lines in x^2-xy-6...

The angle between the lines in `x^2-xy-6y^2-7x+31y-18=0` is

A

`(pi)/(4)`

B

`(pi)/(6)`

C

`(pi)/(2)`

D

`(pi)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
Given equation is `x^2-xy-6y^2-7x+31y-18=0`
Here ,`a=1,b=-6,h=(-1)/(2)`
`therefore theta= tan^(-1)|(2sqrt((-(1)/(2))^2-1xx(-6)))/(1+(-6))|`
`=tan^(-1)|(2sqrt((1)/(4)+6))/(-5)|`
`=tan^(-1)|(5)/(-5)|`
`=tan^(-1)|-1|=(pi)/(4)`
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