If OA is equally inclined to OX,OY ,OZ and if A is `sqrt(3)` units from the origin then the cordinates of A are

Options

A. (3,3,3)
B. (-1,1,-1)
C. )-1,1,1)
D. (1,1,1)

Answer

D

Explanation

Since, OA is equally inclined to OX,OY and OZ
So, coordinates of A are (a,a,a)
Also, OA `=sqrt3`
`therefore" "sqrt((a-0)^2+(a-0)^2+(a-0)^2)=sqrt3`
`rArr" "sqrt(3a^2)=sqrt(3)rArra=pm1`
`therefore` Coordinates of A are (1,1,1) or (-1,-1,-1)