Let O be the origin and P be the point at a distance 3 units from origin. If direction ratios of OP are (1,-2,-2), then coordinates of P is given by

Options

A. (1,-2,-2)
B. (3,-6,-6)
C. `(1//3,-2//3,-2//3)`
D. `(1//9,-2//9,-2//9)`

Answer

A

Explanation

`therefore` Direction cosines of OP are `(1/3,(-2)/3,(-2)/3)` also OP=r=3
Now, point P is given by P(lr,mr,nr).
i.e., `P(x,y,z)=P[1/3(3),-(2/3)3,(-2/3)3]=P(1,-2,-2)`