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If f(x)={{:((log x-log3)/(x-3),"for "x n...

If `f(x)={{:((log x-log3)/(x-3),"for "x ne 3),(c,"for "x =3):}` is continuous at x = 3, then the value of c is

A

3

B

2

C

`(1)/(3)`

D

`(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

Given `f(x)={((logx-log3)/(x-3)",",x ne 3),(C",",x =3):}`
Since f(x) is continuous at x = 3
`therefore f(3)=lim_(x to 3)f(x)`
`rArr C=lim_(x to 3) (logx-log 3)/(x-3)=lim_(x to 3) ((1)/(x))/(1)" " `[by L' Hospital's rule]
`=(1)/(3)`
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