lim(x to 1)(log ex)^(1//logx) is equal t...

`lim_(x to 1)(log ex)^(1//logx)` is equal to

`e^(-1)`

`e^(2)`

Verified by Experts

The correct Answer is:

`lim_(x to 1) (log ex)^(1//logx)=lim_(x to 1)[log e+log x]^(1//logx)`
`=lim_(x to 1)[1+logx]^(1//log x)=e^(lim_(x to 1)(log x)/(log x))=e`

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