Home
Class 12
MATHS
The area enclosed by y = 3x - 5, y = 0, ...

The area enclosed by y = 3x - 5, y = 0, x = 3 and x = 5 is

A

12 sq units

B

13 sq units

C

`13(1)/(2)` sq units

D

14 sq units

Text Solution

Verified by Experts

The correct Answer is:
D

Required area `=int_(3)^(5)(3x-5)dx`
`=((3x^(2))/(2)-5x)_(3)^(5)=((75)/(2)-25)-((27)/(2)-15)`
`=(75)/(2)-25-(27)/(2)+15=(48)/(2)-10=14` sq units
Promotional Banner

Topper's Solved these Questions

  • APPLICATIONS OF DEFINITE INTEGRALS

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Exercise 2|34 Videos
  • APPLICATIONS OF DEFINITE INTEGRALS

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|6 Videos
  • APPLICATIONS OF DERIVATIVES

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET CORNER|21 Videos

Similar Questions

Explore conceptually related problems

Area enclosed by y=2x-x^(2) and y+3=0

If S be the area of the region enclosed by y=e^(-x^(2)), y=0, x=0 and x = 1. Then :

the area enclosed between y=3x and y=x^(2) is

The total area enclosed by the lines y=|x|,y=0 and |x|=1 is

The area enclosed by the line 2x + 3y = 6 along X-axis & the lines x = 0 , x = 3 is ……… sq. units.

Find the area enclosed by the curve [x + y] + [x - y] = 5, for x ge y AA x, y ge 0 .