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A box contains 100 bulbs out of which 10...

A box contains 100 bulbs out of which 10 are defective. A sample of 5 bulbs is drawn. The probability that none is defective , is

A

`10^(-1)`

B

`((1)/(2))^(5)`

C

`((1)/(10))^(5)`

D

`(9)/(10)`

Text Solution

Verified by Experts

The correct Answer is:
C

The repeated selection of bulbs from a box are Bernoulli trials . Let X denotes the number of defective bulbs out of a sample of 5 bulbs.
Now, probability of getting a defective bulbs.
`p=(10)/(100)=(1)/(10)`
and `q=1-p=1-(1)/(10)=(9)/(10)`
clearly, X is binominal distribution with n=5
`p=(1)/(10) and q=(9)/(10)`
`therefore P(X=r)=""^(n)C_(r)p^(r)q^(n-r)`
`=""^(5)C_(r).((1)/(10))^(r)((9)/(100))^(5-r)`
P(all bulbs ares defective
`=P(X=5)=""^(5)C_(5)*((1)/(10))^(5)((9)/(10))^(0)`
`=((1)/(10))^(5)`
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