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The particular solution of the different...

The particular solution of the differential equation `y'+3xy=x` which passes through (0,4) is

A

`y=1-11e^(-3x^(2)//2)`

B

`3y=1+11e^(-3x^(2)//2)`

C

`3y=1-11e^(-3x^(2)//2)`

D

none of these

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The correct Answer is:
To solve the differential equation \( y' + 3xy = x \) that passes through the point (0, 4), we will follow these steps: ### Step 1: Identify the form of the differential equation The given equation is a first-order linear differential equation of the form: \[ \frac{dy}{dx} + P(x)y = Q(x) \] where \( P(x) = 3x \) and \( Q(x) = x \). **Hint:** Recognize the standard form of a linear differential equation. ### Step 2: Calculate the integrating factor The integrating factor \( \mu(x) \) is given by: \[ \mu(x) = e^{\int P(x) \, dx} = e^{\int 3x \, dx} = e^{\frac{3x^2}{2}} \] **Hint:** The integrating factor is derived from the function \( P(x) \) in the equation. ### Step 3: Multiply the entire differential equation by the integrating factor Multiply the equation by \( \mu(x) \): \[ e^{\frac{3x^2}{2}} \frac{dy}{dx} + 3x e^{\frac{3x^2}{2}} y = x e^{\frac{3x^2}{2}} \] **Hint:** This step helps to simplify the left-hand side into a single derivative. ### Step 4: Rewrite the left-hand side as a derivative The left-hand side can be rewritten as: \[ \frac{d}{dx} \left( y e^{\frac{3x^2}{2}} \right) = x e^{\frac{3x^2}{2}} \] **Hint:** Use the product rule of differentiation to combine terms. ### Step 5: Integrate both sides Integrate both sides with respect to \( x \): \[ \int \frac{d}{dx} \left( y e^{\frac{3x^2}{2}} \right) dx = \int x e^{\frac{3x^2}{2}} \, dx \] This gives: \[ y e^{\frac{3x^2}{2}} = \int x e^{\frac{3x^2}{2}} \, dx + C \] **Hint:** The right-hand side requires integration by substitution. ### Step 6: Solve the integral on the right-hand side Let \( t = \frac{3x^2}{2} \), then \( dt = 3x \, dx \) or \( dx = \frac{dt}{3x} \). The integral becomes: \[ \int x e^{\frac{3x^2}{2}} \, dx = \int e^{t} \frac{dt}{3} = \frac{1}{3} e^{t} + C = \frac{1}{3} e^{\frac{3x^2}{2}} + C \] **Hint:** Use substitution to simplify the integral. ### Step 7: Substitute back into the equation Substituting back, we have: \[ y e^{\frac{3x^2}{2}} = \frac{1}{3} e^{\frac{3x^2}{2}} + C \] ### Step 8: Solve for \( y \) Now, divide both sides by \( e^{\frac{3x^2}{2}} \): \[ y = \frac{1}{3} + Ce^{-\frac{3x^2}{2}} \] **Hint:** Isolate \( y \) to express it in terms of \( C \). ### Step 9: Use the initial condition to find \( C \) We know that the solution passes through the point (0, 4): \[ 4 = \frac{1}{3} + Ce^{0} \implies 4 = \frac{1}{3} + C \implies C = 4 - \frac{1}{3} = \frac{12}{3} - \frac{1}{3} = \frac{11}{3} \] **Hint:** Substitute the initial condition to find the constant \( C \). ### Step 10: Write the particular solution Substituting \( C \) back into the equation gives: \[ y = \frac{1}{3} + \frac{11}{3} e^{-\frac{3x^2}{2}} \] **Final Result:** The particular solution of the differential equation that passes through (0, 4) is: \[ y = \frac{1}{3} + \frac{11}{3} e^{-\frac{3x^2}{2}} \] ---
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