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(p^^~q)^^(~p^^q) is...

`(p^^~q)^^(~p^^q)` is

A

a tautology

B

a contradication

C

tautology and contradiction

D

neither a tautology nor a contradiction

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The correct Answer is:
B
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STATEMENT-1 : (p^^~q)^^(~p^^q) and STATEMENT-2 : (pvv~q) vv (~p ^^q)

The simplified form of (p^^q)vv(p^^~q) is

(p ^^ ~q) ^^ (~p vv q) is

The Boolean Expression (p^^~ q)vvqvv(~ p^^q) is equivalent to : (1) ~ p^^q (2) p^^q (3) pvvq (4) pvv~ q

"The negation of the statement =" [(~p^^q)vv(p^^~q)] " is "

Show that ~(p harr q) -= ( p ^^ ~q) vv(~p ^^q) .

The logically equivalent proposition of p hArr q is (p^^q)vv(p^^q) b.(p rArr q)^^(p rArr q) c.(p^^q)vv(p rArr q) d.(p^^q)o+(p vv q)

Using the truth table, prove the following logical equivalence : p hArr q -= (p ^^ q) vv(~p ^^~q) .

Quivalent circuit for the logical expression (~p ^^ q) vv (~p ^^ ~q) vv (p ^^ ~q) is

Show that ( p vee q) ^^ ( ~ p ^^ ~ q) is a contradion .

MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-MOCK TEST 4-MCQS
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