The sides of a rectangle are given by `x=+-a` and `y=+-b`. The equation of the circle passing through the vertices of the rectangle is

Options

A. `x^(2)+y^(2)=a^(2)`
B. `x^(2)+y^(2)=a^(2)+b^(2)`
C. `x^(2)+y^(2)=a^(2)-b^(2)`
D. `(x-a)^(2)+(y-b)^(2)=a^(2)+b^(2)`

Answer

B

Explanation

Given sides of rectangle are
`x=+-a` and `y=+-b`
`therefore` Centre circle=(0,0)
and radius of ricle `=sqrt(a^(2)+b^(2))`

`therefore`Equation of circle `x^(2)+y^(2)=(a^(2)+b^(2))`