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In a standing wave pattern in a vibrating air column, nodes are formed at a distance of 4.0 cm. If the speed of sound in air is` 328 ms^-1` what is the frequency of the source ?

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The correct Answer is:
A, D
Here given distance between two nodes is =4.0 cm
`rarr lamda=2xx4.0=8cm`
we know that `v=nlamda`
`rarr n=328/(8xx10^-2)=4.21KHz`
`=v=340 m/s`
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HC VERMA-SOUND WAVES-Exercises
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  2. A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find...

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  3. In a standing wave pattern in a vibrating air column, nodes are formed...

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  4. The separation between a node and the next antinode in a vibrating air...

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  5. A cylindrical metal tube has a length of 50 cm and is open at both end...

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  6. In a resonance column experiment, a tuning fork of frequency 400 Hz is...

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  7. The first overtone frequency of a closed organ pipe P1 is equal to the...

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  8. A copper rod of length 1.0 m is clamped at its middle point. Find the ...

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  9. Find the greatest length of an organ pipe open at both ends that will ...

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  10. An open organ pipe has a length of 5 cm. (a) Find the fundamental freq...

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  12. Two successive resonance frequencies in an open organ pipe are 1944 Hz...

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  14. A U-tube having unequal arm-lengths has water in it. A tuning fork of ...

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  15. Consider the situation shown in figure. The wire which has a mass of 4...

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  16. A 30.0-cm-long wire having a mass of 10.0 g is fixed at the two ends a...

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  19. A Kundt's tube apparatus has a copper rod of length 1.0 m clamped at 2...

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