The first overtone frequency of a closed organ pipe `P_1` is equal to the fundamental frequency of an open organ pipe `P_2`. If the length of the pipe `P_1` is 30 cm, what will be the length of` P_2`?

Answer

B, C

Explanation

According to the questions
`f_1` first overtone of a closed organn pipe
`P_1=(3v)/(4I)=((3xxV)/(4xx30))
`=f_2=` fundamental frequency of a open organ pipe
`P_2=(V/(2I_2))`
`Here given ((3xxV)/(4xx30))=V/(2I_2)`
`rarr I_2=20cm`
`:. length of the pipe `P_2` will be 20 cm.