A constant volume thermometer registers o pressure of `1.500 xx 10^4` Pa at the triple point of water and a pressure of `1.500 xx 10^4` Pa at the normal boiling point. What is the temperature at the normal boiling point?

Explanation

Given `P_tr=(1.500 xx 10^4 Pa)`
`P=2.050 xx 10^4 Pa`
we know, for constant volume gas thermometer
`T =P/P_tr xx 273.16 K` `=(2.050 xx 10^4) / (1.5 xx 10^4) xx 273.16`
`=373.31`