The pressure measured by a constant volume gas thermometer is 40 kPs at the triple point of water. What will be the pressure measured at the boiling point of water `(100^ C)`?

Explanation

Given, `P_tr =40 xx 10^3 Pa`, P=?`
` T=100^0 C= 373K`
`T=P/ P_tr xx 273.16`
` rArr P=T xx P_tr/ 273.16` (373 xx 40 xx 10^3)/(273.16)`
`= 54620 Pa`
`= 54.6 xx 10^3 Pa =55KPa`