A circular hole of diameter 2.00 cm is made in an alumimium ate at `0^C`. What will be the diameter at `100^C`? Alpha for aluminium `=2.3 xx 10^(-5) 0^C^(-1).

Explanation

`D_1=2cm =2xx 10^-2m`, d_2=?`
`t_1 = 0 ^0C, t_2= 100^@C ` V ` alpha al = 2.3 xx 10^-5 /^0C `
`:.d_2=d_1 (1+alpha Delta t)`
`=2xx10^-2(1+2.3xx 10^-5xx 10^2)`
`= 2 xx 10^-2( 1+2.3 xx 10^-3)`
`=2xx 10^-2+2.3xx 2xx 10^-5 `
`= 0.02+0.000046`
`=0.020046m~~ 2.0046cm `