` (dy)/(dx) ` ज्ञात कीजिए , जबकि ` x = a ( cos t + log_(e) tan . t/2), y = a sin t `

Explanation

यहाँ ` (dy)/(dt) = a cos t `
और ` (dx)/(dt) = a ( -sin + 1/(tan.(1)/2t )* sec^(2). (t)/2 1/2 )`
` = a ( -sin t + 1/(2sin. 1/2 t cos 1/2 t ))`
` a ( - sin t + 1/(sin t ) )`
` = a ( (-sin^(2) t +1)/(sin t ) ) = ( a cos^(2) t)/(sint) `
` :. (dy)/(dx) = ( dy//dt)/(dx//dt) = ( a cos t) xx (sin t) /(a cos^(2) t) = (sin t) /(cost) = tan t . `