`x = cos theta - cos 2 theta , y = sin theta , (dy)/(dx)` ज्ञात कीजिए ।

Explanation

` y = sin theta - sin theta `
` (dy)/(dx) = cos theta - 2 cos 2 theta `
` x = cos theta - cos 2 theta `
` (dx)/(dy) = (dy)/(dx) /(dx)/(dy) `
` = ( cos theta - 2 cos theta 2 theta )/( -sin theta + 2 sin2 theta )`
` ( cos theta - 2 cos 2 theta )/(2 sin 2 theta - sin theta )` 14