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int[1/logx-1/(logx)^2]dx=...

`int[1/logx-1/(logx)^2]dx=`

A

`(x)/(log x)+c`

B

x.logx+c

C

`(x)/((log x)^(2))+c`

D

`e^(x).logx+c`

Text Solution

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The correct Answer is:
A
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