Two coins are tossed simutlaneously. What is the probability of getting at least one tail ?

Answer

`3/4`

Explanation

Let S be the sample space
Then `S={HH, HT, TH, T T}.`
`therefore n(S)=4.`
(i) Let A be the event where at least one tail turns up.
Then `A={HT, TH, T T }`
`therefore n(A)=3.`
`P(A) =(n(A))/(n(S))" "therefore P(A)=3/4.`