There are 3 red, 3 white and 3 greeen balls, of the same size, in a box. One ball is drawn at random from the box.Find number of outcomes in: (i) A is the event of neither getting a red ball nor getting a green ball. (ii) B is the event of getting a red ball or green ball.

Explanation

`S={R_(1), R_(2),R_(3),W_(1), W_(2), W_(3), G_(1), G_(2), G_(3)}, n(S)=9`
(i) `A+{W_(1),W_(2),W_(3)},n(A)=3`
`(ii) B={R_(1), R_(2), R_(3), G_(1), G_(2), G_(3)}, n(B)=6`