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A small air bubble of radius r in water ...

A small air bubble of radius r in water is at a depth h `( r lt lt h )`. If `P_(o)` is the atmospheric pressure, `rho` is the density of water and T is the surface tension of water, the excess pressure inside the bubble over the pressure outside it is

A

`rho gh+(4T)/(r)`

B

`(4T)/( r)`

C

`(2T)/(r )`

D

`rho gh+(2T)/(r)`

Text Solution

Verified by Experts

The correct Answer is:
C
The pressure at the depth h outside the bubble `=p_(0)+rho gh.`
`therefore` The excess pressure inside the bubble `=p-(p_(0)+rho gh)=(2T)/(R )`
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