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The linear speed of a particle revolved ...

The linear speed of a particle revolved in a vertical circle of radius r is `sqrt(7gr)` at the lowest point. What is the linear speed half way to the top?

Text Solution

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If `v_b " and " v_m` are the speeds of the particle at the bottom and midway point, from energy coservation principle,
`1/2mv_m^2+mgr=1/2mv_b^2=7/2mgr`
`therefore v_m^2+2gr=7gr " " therefore v_m=sqrt(5gr)`
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