If a bodyof mass 1000 gm is tied to free end of string of length 100 cm and whirled in a horizontal circle in a second, then the tecsion in the string will be

Explanation

Data : m = 100 g = 0.1 kg, r=4 m, g = 9.8 ` m//s^(2)`
F = 45 kg wt = ` 45 xx 9.8 ` N
The maximum centripetal force that can be applied is equal to the breaking tension.
` m omega_(max)^(2) r= F_(max)`
` m(4pi^(2) f_(max)^(2)) r= F_(max)`
The maximum number of revolutions per second .
` f_(max) = sqrt(F_(max)/(4pi^(2)mr)) = sqrt((45xx9.8)/(4xx(3.142)^(2)xx 0.1 xx4)) = 5.283 Hz`