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A stone of mass 100 g attached to a stri...

A stone of mass 100 g attached to a string of length 50 cm is whirled in a vertical circle by giving it a velocity of 7 m/s at the lowest point. Find the velocity at the highest point .

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AI Generated Solution

To find the velocity of the stone at the highest point of its vertical circular motion, we can follow these steps: ### Step 1: Identify the given values - Mass of the stone, \( m = 100 \, \text{g} = 0.1 \, \text{kg} \) (since 1 g = 0.001 kg) - Length of the string (radius of the circle), \( r = 50 \, \text{cm} = 0.5 \, \text{m} \) (since 1 cm = 0.01 m) - Velocity at the lowest point, \( v_1 = 7 \, \text{m/s} \) ### Step 2: Calculate the total energy at the lowest point ...
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Knowledge Check

  • A stone of mass 250 gram , attached at the end of a string of length 1.25 m is whirled in a horizontal circle at a speed of 5 m/s . What is the tension in the string ?

    A
    `2.5N`
    B
    5N
    C
    6N
    D
    8N

  • A body of mass 100 gram is tied at the end of a string of length 1m. It is rotated in a vertical circle at a critical speed of 4 m/s at the highest point . The tension in the string at the huighest point in its path is [ take g=10 m//s^(2) ]

    A
    `0.3N`
    B
    `0.6N`
    C
    `0.9N`
    D
    `1.2N`

  • A stone of mass 0.5 kg is attached to a string of length 2m and is whirled in a horizontal circle. If the string can withstand a tension of 9N, the maximum velocity with which the stone can be whirled is

    A
    `6 ms^(-1)`
    B
    `8 ms^(-1)`
    C
    `4 ms^(-1)`
    D
    `12 ms^(-1)`

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