A conical pendulum has length of 1.1 m and the angle subtended by the string with the vertical is `25^(@)31`. Find (i) the angular speed (ii)the frequency of circular motion of the bob.

Explanation

Data : L = 1.1 m , `theta= 25^(@)31 , g = 9.8 m//s^(2)`
(i) The angular speed, ` omega = sqrt(g/(L cos theta))`
` sqrt((9.8)/(1.1 xx cos 25^(@)31)) = sqrt(98/(11 xx 0.9025))`
(iii) The frequency ` f= omega/(2pi) = (3.142)/(2xx 3.142) = 0.5 rps`