An aeroplane flying in the sky dives with a speed of `360 km//h` in a verticale circle of radius 200 m The weight of pilot sitting in it is 75 kg Calulate the force with which the pilot presses his seat when the aeroplane is (i) at the lowest position and (ii) at the highest position Take ` g = 10 m//s^(-2)` .

Explanation

Data ` v = 360 xx 5/18 m//s = 100 m//s ` r= 200 m
m =75 kg, g = 9.8 `m//s^(2)`
(i) At the highest position.
` N_(1) = m(v^(2)/r -g) = 75 [((100)^(2))/200 - 9.8] = 75 ( 50 -9.8) `
75 (40.2) - 3015 N
(ii) At the lowest position .
`N_(2) = m(v^(2)/r+g)`
` = 75 [ ((100)^(2))/200 + 9.8 ] = 75 ( 50 + 9.8 ) = 75 (59.8) = 4485 N`
The forces exerted by the seat on the pilot at the highest and lowest position are 3015 N and 4486 N, respectively.