A steel wire having cross-sectional area 2 mm^(2)` is stretched by 20 N. Find the lateral strain produced in the wire Y_("steel") = 2 xx 10^(11) Nm^(-2), sigma = 0.391

Explanation

Data : ` A = 2 mm^(2) = 2 xx 10^(-6) m^(2) , F= 10 N, Y = 2 xx 10^(11) N//m^(2) sigma = 0.29`
` Y = (F//A)/(" longitudinal strain") " " therefore " Longitudinal strain " = F/(AY)`
` sigma = (" laternal strain")/("longitudinal strain") `
Laternal strain ` sigma xx ` longitudinal strain
` = (sigmaF)/(AY) = (0.29 xx 10)/(2xx10^(-6) xx2 xx 10^(11)) = 2.9/4 xx 10^(-5)`
` 29/4 xx 10^(-6) = 7.25 xx 10^(-6)`