What is the emissive power of a perfect blackbody at 1000 K ?

Explanation

To find the emissive power of a perfect blackbody at a temperature of 1000 K, we can use the Stefan-Boltzmann Law, which states that the emissive power (E) of a blackbody is given by the formula:

\[ E = \sigma T^4 \]

where:
- \( E \) = emissive power (W/m²)
- \( \sigma \) = Stefan-Boltzmann constant \( \approx 5.67 \times 10^{-8} \, \text{W/m}^2\text{K}^4 \)
- \( T \) = absolute temperature in Kelvin (K)
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