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Two slits in Young's experiment have wid...

Two slits in Young's experiment have widths in the ratio `8100 : 7255`. What is the ratio of the amplitude of light waves issuing out from them?

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`(w_(1))/(w_(2)) = I_(1)/I_(2) = (A_(1)/A_(2))^(2)`, since `I propto A^(2)`,
`therefore` The required ratio `A_(1)/A_(2) = sqrt(omega_(1)/omega_(2)) = sqrt(8100/7225) = sqrt(324/289)= 18/17`
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NAVNEET PUBLICATION - MAHARASHTRA BOARD-SOLVED PROBLEMS-II -Interference and Diffraction
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