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The electron in a hydrogen atom revolves...

The electron in a hydrogen atom revolves in an orbit of radius `0.5 Å`, constituting a conventional current of 1.1 mA. Calculate the magnetic induction at an axial point 100 `Å` from the nucleus of the atom.

Text Solution

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Data: `r=0.5 Å= 5 xx 10^(-11), I=1.1 xx 10^(-3) A, x=100 Å= 10^(-8)m, (mu_(0))/(4pi) = 10^(-7) T.m//A`
The magnitude of the magnetic induction at an axial point of a current loop,
`B=(mu_(0))/(4pi). (2IA)/(r^(2) + x^(2))^(3//2) ~= (mu_(0))/(4pi)(2IA)/(x^(3)) (therefore x^(2) gt gt R^(2))`
`=(mu_(0))/(4pi)(2I(pir^(2)))/(x^(3))`
`=(10^(-7))(2(1.1 xx 10^(-3))(3.142)(5 xx 10^(-11))^(2))/(10^(-8))^(3)`
`=3.142 xx 55 xx 10^(-8) = 1.728 xx 10^(-6)` T
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