The magnetic field `B` and the magnetic intensity `H` in a material are found to be `1.6 T and 1000 A m^(-1)` respectively. Calculate the relative permeability `mu`, and the susceptibility `chi` of the material.

Explanation

Data: `B=1.6 T, H=1000 A//m, mu_(0) = 4pi xx 10^(-7) T.m//A`
(i) `B=muH = mu_(0)mu_(r)H`
`therefore` The relative permeability of the material,
`mu_(r) = B/(mu_(0)H)= 1.6/((4 xx 3.142 xx 10^(-7))(10^(3)))`
(ii) `mu_(r) = 1+X_(m)`
`therefore` The magnetic susceptibility of the material,
`X_(m) = mu_(r)-1 = 1273 -1 = 1272 = 1.272 xx 10^(3)`