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Find the wave number of a photon having ...

Find the wave number of a photon having an energy of 2.072 eV.
Given :
Charge on electron `=1.6xx10^(-19)C`
Velocity of light air `=3xx10^(8)" m"//"s"`
Planck's constant `=6.63xx10^(-34)" J-s"`.

Text Solution

Verified by Experts

Data: `e=1.6 xx 10^(-19) C, c=3 xx 10^(8) m//s, h=6.63 xx 10^(-34)` J.s, `e=2.072 eV = 2.072 xx 1.6 xx 10^(-19)` J
`E=hv= (hc)/lambda`
`therefore` Wave number, `1/lambda = E/(hc) = (2.072 xx 1.6 xx 10^(-19))/((6.63 xx 10^(-34))(3 xx 10^(8)))`
`=(3.3152)/(19.89) xx 10^(7) = (33.15)/(19.89) xx 10^(6)`
`=1.666 xx 10^(6) m^(-1)`
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