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Specific latent of fusion of ice is 80 c...

Specific latent of fusion of ice is 80 cal/g. Explain this statement ?

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When 1g o ice at a pressure of one atmosphere and at a temperature `0^(@)C` is converted into 1 g of water, heat absorbed by the ice is 80 cal.
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(1) Take a few pieces of ice in a glass beaker as shown in figure. (2) Insert the bulb of a thermometer in ice and measure its temperature. (3) Put the beaker on a stand and heat the ice using a burner. (4) Record the temperature using the thermometer after every minute. (5) As the ice is heated,it starts melting. Stir the mixture of ice and water. (6) Continue the heating even after ice starts melting. (7) Draw a graph of temperature versus time. The specific latent heat of fusion of ice is 80 cal // g .Explain this statement .

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The specific latent heat of fusion of ice is …………….

A vessel with 100 g of water at a temperature of 0^(@)C is suspended in the middle of a room. In 15 minutes the temperature of the water rises to 1.8^(@)C . When ice equal in weight of the water is placed in the same vessel, it melts during 10 hours. using appropriate appropriate approximations, estimate the latent heat of fusio of ice in cal/g. if the known alue of latent heat of fusion of ice is 80 cal/g, obtain the difference in the two values in cal/g and report this as your answer.

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