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From an octahedral splitting arrangement...

From an octahedral splitting arrangement if two ligans present along Z-axis are removed then what will be the correct order of energy for 5d-orbitals of central metal?

A

`d_(x^(2)-y^(2))gtd_(xy)gtd_(z^(2))gtd_(xz)=d_(yz)`

B

`d_(xy)gtd(x^(2)-y^(2))gtd_(z^(2))gtd_(xz)gtd_(yz)`

C

`d_(z^(2))gtd_(xz)=d_(yz)gtd_(xy)gtd_(x^(2)-y^(2))`

D

`d_(x^(2)-y^(2))=d_(z^(2))gtd_(xy)=d_(yz)=d_(xz)`

Text Solution

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The correct Answer is:
A
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According to cystal field theory, interaction between central metal atom/ion and ligand is electrostatic in nature. In free metal ions, the five d-orbitals are degenerate. However, in a ligand field e.g., tetrahedral, octahedral, square planar, square pyramidal, trigonal bipyramidal, the degeneracy of 5d-orbitals is lost. If lobes of d-orbitals of central metal atom/ion are along the axes through which ligands are approaching, the energy of corresponding d-orbital is raised more than the d-orbitals having lobes between teh axes. e.g., octahedral complexes, square planar complexes, square pyramidal compexes. The correct order Delta_(o), Delta_(t)" and "Delta_(sp) (where o, t and sp stand for octahedral, tetrahedral and square planar fileds respectively) is :

According to cystal field theory, interaction between central metal atom/ion and ligand is electrostatic in nature. In free metal ions, the five d-orbitals are degenerate. However, in a ligand field e.g., tetrahedral, octahedral, square planar, square pyramidal, trigonal bipyramidal, the degeneracy of 5d-orbitals is lost. If lobes of d-orbitals of central metal atom/ion are along the axes through which ligands are approaching, the energy of corresponding d-orbital is raised more than the d-orbitals having lobes between teh axes. e.g., octahedral complexes, square planar complexes, square pyramidal compexes. Which of the following orbitals has the highest energy in square pyramidal ligand field ?